Based on Chapter 8 of ModernDive. Code for Quiz 12.
Replace all the instances of ‘SEE QUIZ’. These are inputs from your moodle quiz.
Replace all the instances of ‘???’. These are answers on your moodle quiz.
Run all the individual code chunks to make sure the answers in this file correspond with your quiz answers
After you check all your code chunks run then you can knit it. It won’t knit until the ??? are replaced
The quiz assumes that you have watched the videos and worked through the examples in Chapter 7 of ModernDive
Question 7.2.4 in Modern Dive with different sample sizes and repetitions
tidyverse
and the moderndive
packagesbowl
Segment 1: sample size = 26
1.a) Take 1180 samples of size of 26 instead of 1000 replicates of size 25 from the bowl
dataset. Assign the output to virtual_samples_26
virtual_samples_26 <- bowl %>%
rep_sample_n(size = 26, reps = 1180)
1.b) Compute resulting 1180 replicates of proportion red start with virtual_samples_26 THEN group_by replicate THEN create variable red equal to the sum of all the red balls create variable prop_red equal to variable red / 26 Assign the output to virtual_prop_red_26
virtual_prop_red_26 <- virtual_samples_26 %>%
group_by(replicate) %>%
summarize(red = sum(color == "red")) %>%
mutate(prop_red = red / 26)
1.c) Plot distribution of virtual_prop_red_26 via a histogram use labs to
ggplot(virtual_prop_red_26, aes(x = prop_red)) +
geom_histogram(binwidth = 0.05, boundary = 0.4, color = "white") +
labs(x = "Proportion of 26 balls that were red", title = "26")
Segment 2: sample size = 55
2.a) Take 1180 samples of size of 55 instead of 1000 replicates of size 50. Assign the output to virtual_samples_55
virtual_samples_55 <- bowl %>%
rep_sample_n(size = 55, reps = 1180)
2.b) Compute resulting 1180 replicates of proportion red
virtual_prop_red_55<- virtual_samples_55 %>%
group_by(replicate) %>%
summarize(red = sum(color == "red")) %>%
mutate(prop_red = red / 55)
2.c) Plot distribution of virtual_prop_red_55 via a histogram use labs to
ggplot(virtual_prop_red_55, aes(x = prop_red)) +
geom_histogram(binwidth = 0.05, boundary = 0.4, color = "white") +
labs(x = "Proportion of 55 balls that were red", title = "55")
Segment 3: sample size = 110
3.a) Take 1180 samples of size of 110 instead of 1000 replicates of size 50. Assign the output to virtual_samples_110
virtual_samples_110 <- bowl %>%
rep_sample_n(size = 110, reps = 1180)
3.b) Compute resulting 1180 replicates of proportion red
virtual_prop_red_110 <- virtual_samples_110 %>%
group_by(replicate) %>%
summarize(red = sum(color == "red")) %>%
mutate(prop_red = red / 110)
3.c) Plot distribution of virtual_prop_red_110 via a histogram use labs to
ggplot(virtual_prop_red_110, aes(x = prop_red)) +
geom_histogram(binwidth = 0.05, boundary = 0.4, color = "white") +
labs(x = "Proportion of 110 balls that were red", title = "110")
Calculate the standard deviations for your three sets of 1180 values of prop_red using the standard deviation n = 26
virtual_prop_red_26 %>%
summarize(sd = sd(prop_red))
# A tibble: 1 x 1
sd
<dbl>
1 0.0904
n = 55
virtual_prop_red_55 %>%
summarize(sd = sd(prop_red))
# A tibble: 1 x 1
sd
<dbl>
1 0.0647
n=110
virtual_prop_red_110 %>%
summarize(sd = sd(prop_red))
# A tibble: 1 x 1
sd
<dbl>
1 0.0449
The distribution with sample size, n = 110, has the smallest standard deviation (spread) around the estimated proportion of red balls.